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Elastic Potential Energy
Jamie Z 2024-06-18Learning Goals
- Describe elastic potential energy as energy stored in springs and elastic bands
- Solve problems involving Hooke’s law
Hooke’s Law
\[ F_s = kx \]
- F = Force (N)
- x = Displacement (m)
- k = Spring Constant (N/m)
Example
A spring of unextended length 20cm and spring constant 22N/m supports a mass of 250g. What is the new length of the spring
\[ F=ma \ = 0.25*9.8 \=2.45 \]
\[ F_s = kx \ 2.45 = 22x \ x=\frac{2.45}{22} \ x=0.11 \]
- Therefore, the new length of the spring is 31cm long
Elastic Potential Energy
- The energy stored as a result of applying a force to deform an elastic object
- The graph of F vs x for a spring that is IDEAL in nature will always produce a line with a positive linear slope. Thus the area under the line will always be represented as a triangle

\[ U_s = \frac{1}{2}kx^2 \]